Imagine you're driving a car. Your speedometer doesn't show your average speed over the whole trip — it shows how fast you're going right now, at this exact moment. That's a derivative.
In mathematics, a derivative tells you how fast a function is changing at any given point. If you draw the graph of a function, the derivative at a point gives you the slope of the tangent line — the line that just barely touches the curve at that point.
A positive derivative means the function is going up. A negative derivative means it's going down. A derivative of zero means the function has leveled off — you're at a peak, a valley, or a flat section.
Position is a function of time: f(t). The derivative f′(t) is your velocity — how quickly your position is changing. The derivative of velocity is acceleration — how quickly your velocity is changing. Every time you ask "how fast is this changing?", you're asking for a derivative.
Take two points on a curve and draw a line through them — that's a secant line, and its slope is the average rate of change. Now slide the two points together until they become one. The secant line becomes a tangent line, and its slope is the derivative. The derivative is what you get when the gap between the two points shrinks to zero.
The derivative of a function \(f\) at a point \(x\) is defined as the limit:
This fraction \(\dfrac{f(x+h)-f(x)}{h}\) is the slope of the secant line between two points separated by a distance \(h\). As \(h \to 0\), the secant line becomes the tangent line, and we get the instantaneous rate of change.
The derivative is also written as \(\dfrac{dy}{dx}\) (Leibniz notation) or \(\dot{f}\) (Newton's dot notation).
| Constant | \(\dfrac{d}{dx}[c] = 0\) |
| Power Rule | \(\dfrac{d}{dx}[x^n] = nx^{n-1}\) |
| Exponential | \(\dfrac{d}{dx}[e^x] = e^x\) |
| Natural Log | \(\dfrac{d}{dx}[\ln x] = \dfrac{1}{x}\) |
| Sine | \(\dfrac{d}{dx}[\sin x] = \cos x\) |
| Cosine | \(\dfrac{d}{dx}[\cos x] = -\sin x\) |
| Sum Rule | \(\dfrac{d}{dx}[f+g] = f' + g'\) |
| Product Rule | \(\dfrac{d}{dx}[fg] = f'g + fg'\) |
| Chain Rule | \(\dfrac{d}{dx}[f(g(x))] = f'(g(x)) \cdot g'(x)\) |
\(f'(x) = 3x^2\)
\(f'(x) = 2x + 5\)
\(f'(x) = 2x\cos(x^2)\)
\(f'(x) = 2xe^x + x^2e^x\)
Ready to test your knowledge?
Take the Calculus I quiz and practice derivative problems with instant feedback.
Go to Calculus I Quizzes →