๐Ÿ“– What Are Nonlinear Functions?

A nonlinear function is a function whose graph is not a straight line. The rate of change is not constant.

Quadratic Function
\(y = ax^2 + bx + c\)
Parabola shape. \(a > 0\) โ†’ opens up, \(a < 0\) โ†’ opens down
Exponential Function
\(y = a \cdot b^x\)
Rapid growth or decay. \(b > 1\) โ†’ growth, \(0 < b < 1\) โ†’ decay
Polynomial Function
\(y = a_n x^n + ... + a_1 x + a_0\)
Multiple terms with non-negative integer exponents
Radical Function
\(y = \sqrt{x}\) or \(y = \sqrt[3]{x}\)
Contains a square root, cube root, or other root

1. Quadratic Functions

\( y = ax^2 + bx + c \)
๐Ÿ“Œ RULE 1: Vertex Formula
The vertex \((h, k)\) is the maximum or minimum point of the parabola.

Step 1: Find the x-coordinate:
\[ h = -\frac{b}{2a} \]

Step 2: Find the y-coordinate by substituting \(h\) back into the equation:
\[ k = a(h)^2 + b(h) + c \]

Vertex: \((h, k)\)
๐Ÿ“Œ RULE 2: Finding Roots (x-intercepts)
Set \( y = 0 \) and factor, or use the Quadratic Formula:

\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
The roots are the x-values where the parabola crosses the x-axis.
๐Ÿ“Œ RULE 3: Y-Intercept
Set \( x = 0 \):

\[ y = a(0)^2 + b(0) + c = c \]
The y-intercept is \((0, c)\).
๐Ÿ“Œ RULE 4: Direction of Opening
\[ a > 0 \quad \rightarrow \quad \text{Opens upward (minimum point)} \]
\[ a < 0 \quad \rightarrow \quad \text{Opens downward (maximum point)} \]
๐Ÿ’ก Strategy โ€” Quadratic Functions

1. Identify \(a\), \(b\), \(c\) from the equation.
2. Use \(h = -\frac{b}{2a}\) to find the vertex's x-coordinate.
3. Substitute \(h\) to find \(k = a(h)^2 + b(h) + c\).
4. Factor or use the quadratic formula for roots.

๐Ÿ“ SOLVED EXAMPLE โ€” Quadratic
Find the vertex and roots of \(y = x^2 - 4x + 3\)
Step 1: Identify \(a = 1\), \(b = -4\), \(c = 3\)
Step 2: Vertex x-coordinate: \(h = -\frac{-4}{2(1)} = \frac{4}{2} = \color{var(--math)}{2}\)
Step 3: Vertex y-coordinate: \(k = (2)^2 - 4(2) + 3 = 4 - 8 + 3 = \color{var(--math)}{-1}\)
Step 4: Vertex: \(\color{var(--math)}{(2, -1)}\)
Step 5: Roots: \(x^2 - 4x + 3 = 0\) โ†’ \((x - 1)(x - 3) = 0\) โ†’ \(x = \color{var(--math)}{1, 3}\)
โœ… Vertex: \((2, -1)\), Roots: \(x = 1, 3\)
๐Ÿ’ก Tip: Since \(a = 1 > 0\), this is a minimum (opens up).

2. Exponential Functions

\( y = a \cdot b^x \)
๐Ÿ“Œ RULE 1: Growth vs. Decay
\[ b > 1 \quad \rightarrow \quad \text{Growth (population growth, investment)} \]
\[ 0 < b < 1 \quad \rightarrow \quad \text{Decay (radioactive decay, depreciation)} \]
\(a\) = initial value (when \(x = 0\))
๐Ÿ“Œ RULE 2: Growth/Decay Factor
If a quantity increases by \(r\%\), then:
\[ b = 1 + \frac{r}{100} \]

If a quantity decreases by \(r\%\), then:
\[ b = 1 - \frac{r}{100} \]
๐Ÿ’ก Strategy โ€” Exponential Functions

1. Identify the initial value \(a\).
2. Determine if it's growth (\(b > 1\)) or decay (\(b < 1\)).
3. Substitute \(x\) to find the value at any time.

๐Ÿ“ SOLVED EXAMPLE โ€” Exponential
$500 invested at 4% annual growth. Find the value after 3 years.
Step 1: Initial value: \(a = 500\)
Step 2: Growth rate = 4% โ†’ \(b = 1 + 0.04 = \color{var(--math)}{1.04}\)
Step 3: \(x = 3\) (years)
Step 4: \(y = 500(1.04)^3 = 500(1.124864) = \color{var(--math)}{562.43}\)
โœ… $562.43 after 3 years
๐Ÿ’ก Tip: Growth factor = \(1 + \text{rate}\) (as a decimal). 4% โ†’ 1.04

3. Polynomial Functions

\( y = a_n x^n + ... + a_1 x + a_0 \)
๐Ÿ“Œ RULE 1: End Behavior
Even degree: Both ends go the same direction.
\[ a > 0 \rightarrow \text{up on both ends} \]
\[ a < 0 \rightarrow \text{down on both ends} \]

Odd degree: Ends go in opposite directions.
\[ a > 0 \rightarrow \text{down on left, up on right} \]
\[ a < 0 \rightarrow \text{up on left, down on right} \]
๐Ÿ“Œ RULE 2: Degree
The highest exponent is the degree of the polynomial.
Example: \(y = 3x^4 - 2x^2 + 1\) โ†’ Degree = 4 (even)
๐Ÿ’ก Strategy โ€” Polynomial Functions

1. Find the leading term (highest degree term).
2. Check the degree and leading coefficient.
3. Determine end behavior using the rules above.

๐Ÿ“ SOLVED EXAMPLE โ€” Polynomial
What is the end behavior of \(y = -2x^3 + x^2 - 5\)?
Step 1: Leading term: \(\color{var(--math)}{-2x^3}\)
Step 2: Degree = 3 (odd), leading coefficient = \(-2\) (negative)
Step 3: Odd degree, negative coefficient โ†’
As \(x \to \infty\), \(y \to \color{var(--math)}{-\infty}\)
As \(x \to -\infty\), \(y \to \color{var(--math)}{\infty}\)
โœ… As \(x \to \infty\), \(y \to -\infty\); as \(x \to -\infty\), \(y \to \infty\)
๐Ÿ’ก Tip: Odd degree, negative leading coefficient โ†’ down on right, up on left.

4. Radical Functions

\( y = \sqrt{x} \) or \( y = \sqrt[3]{x} \)
๐Ÿ“Œ RULE: Domain of Square Root Functions
The expression under the square root must be \(\geq 0\).

Example: \(y = \sqrt{x - 5}\)
\[ x - 5 \geq 0 \quad \rightarrow \quad \boxed{x \geq 5} \]
๐Ÿ’ก Strategy โ€” Radical Functions

1. Set the radicand (inside the root) \(\geq 0\).
2. Solve for \(x\) to find the domain.

๐Ÿ“ SOLVED EXAMPLE โ€” Radical
Find the domain of \(y = \sqrt{x + 3}\)
Step 1: The radicand must be \(\geq 0\): \(x + 3 \geq 0\)
Step 2: \(\color{var(--math)}{x \geq -3}\)
โœ… Domain: \(x \geq -3\)
๐Ÿ’ก Tip: For square roots, the expression under the root must be non-negative.

๐Ÿงช Practice Questions

Solve each problem using the rules above. Click "Show Answer" to see the full solution.

Question 1
Find the vertex of \(y = x^2 - 6x + 8\)
A) \((3, -1)\)
B) \((-3, -1)\)
C) \((3, 1)\)
D) \((6, 8)\)
โœ“ Answer: A
\(a = 1\), \(b = -6\). \(h = -\frac{-6}{2(1)} = 3\). \(k = 9 - 18 + 8 = -1\). Vertex: \((3, -1)\)
๐Ÿ“ Solution: \(h = 3\), \(k = -1\)
Question 2
Find the roots of \(y = x^2 - 7x + 12\)
A) \(x = 2, 6\)
B) \(x = 3, 4\)
C) \(x = 3, 8\)
D) \(x = 2, 5\)
โœ“ Answer: B
\(x^2 - 7x + 12 = 0\) โ†’ \((x - 3)(x - 4) = 0\) โ†’ \(x = 3, 4\)
๐Ÿ“ Solution: \((x - 3)(x - 4) = 0\) โ†’ \(x = 3, 4\)
Question 3
$500 invested at 4% annual growth. What is the value after 2 years?
A) $520
B) $530
C) $550
D) $540.80
โœ“ Answer: D
\(y = 500(1.04)^2 = 500(1.0816) = 540.80\)
๐Ÿ“ Solution: \(500(1.04)^2 = 540.80\)
Question 4
Find the domain of \(y = \sqrt{x + 3}\)
A) \(x \geq 0\)
B) \(x \geq 3\)
C) \(x \geq -3\)
D) \(x > -3\)
โœ“ Answer: C
\(x + 3 \geq 0\) โ†’ \(x \geq -3\)
๐Ÿ“ Solution: \(x + 3 \geq 0\) โ†’ \(x \geq -3\)
Question 5
What is the end behavior of \(y = 3x^4 - 2x^2 + 1\)?
A) As \(x \to \pm\infty\), \(y \to \infty\)
B) As \(x \to \pm\infty\), \(y \to -\infty\)
C) As \(x \to \infty\), \(y \to \infty\); as \(x \to -\infty\), \(y \to -\infty\)
D) As \(x \to \infty\), \(y \to -\infty\); as \(x \to -\infty\), \(y \to \infty\)
โœ“ Answer: A
Leading term: \(3x^4\) (even degree, positive coefficient) โ†’ both ends go up.
๐Ÿ“ Solution: Even degree, positive โ†’ both ends up.
Question 6
What is the y-intercept of \(y = 2x^2 - 5x + 3\)?
A) \((0, 0)\)
B) \((0, 2)\)
C) \((0, 3)\)
D) \((0, 5)\)
โœ“ Answer: C
Set \(x = 0\): \(y = 2(0)^2 - 5(0) + 3 = 3\)
๐Ÿ“ Solution: \(y = 3\) โ†’ \((0, 3)\)
Question 7
A population of 200 bacteria doubles every hour. How many after 3 hours?
A) 400
B) 600
C) 800
D) 1600
โœ“ Answer: D
\(y = 200(2)^3 = 200(8) = 1600\)
๐Ÿ“ Solution: \(200(2^3) = 200(8) = 1600\)
Question 8
Which is NOT a nonlinear function?
A) \(y = x^2 + 3x - 5\)
B) \(y = 2x - 7\)
C) \(y = 2^x\)
D) \(y = \sqrt{x}\)
โœ“ Answer: B
\(y = 2x - 7\) is a linear function. All others are nonlinear.
๐Ÿ“ Solution: \(y = 2x - 7\) is linear (straight line).
Question 9
Find the vertex of \(y = -x^2 + 4x + 1\)
A) \((-2, 5)\)
B) \((2, 5)\)
C) \((2, 3)\)
D) \((-2, 3)\)
โœ“ Answer: B
\(a = -1\), \(b = 4\) โ†’ \(h = -\frac{4}{2(-1)} = 2\). \(k = -4 + 8 + 1 = 5\). Vertex: \((2, 5)\)
๐Ÿ“ Solution: \(a=-1\), \(b=4\) โ†’ \(h=2\) โ†’ \(k=5\)
Question 10
Find the roots of \(y = x^2 - 9\)
A) \(x = \pm 3\)
B) \(x = \pm 9\)
C) \(x = 0, 9\)
D) \(x = 3\) only
โœ“ Answer: A
\(x^2 - 9 = 0\) โ†’ \(x^2 = 9\) โ†’ \(x = \pm 3\)
๐Ÿ“ Solution: \(x^2 = 9\) โ†’ \(x = 3\), \(x = -3\)
๐ŸŽ‰ WELL DONE!

You've completed the Nonlinear Functions lesson. You now know the rules for quadratic, exponential, polynomial, and radical functions.

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